Let me answer your question first. Since this circuit has a single loop, the current does not branch off anywhere and so the current is the same everywhere in the circuit. So to use Kirchoff's Laws for this circuit, you would only have one current i.conage wrote: ↑Mon Jul 23, 2018 5:50 amI was having trouble uploading an image but I think it's okay now. The question is:
Calculate the current in the circuit of Fig. 19-53, and show that the sum of all the voltage changes around the circuit is zero.
I know we have to use kirchoff's law and we have one loop on the inside. How do we know where to put i1 and I2?
However, I don't believe they actually want you to use Kirchoff's voltage law for this one. They want you to show that the sum of the voltage changes is zero, but that's the starting point for the Voltage Law.
(In other words, this problem is not about using Kirchoff's law, it's about proving that it works in this case.)
So here's what I would suggest, since these resistors are all in series:
- combine these series resistors into one equivalent resistor
- use the equivalent resistance and the battery voltage in Ohm's Law to find the total current
- for each resistor, use Ohm's law and the total current to find the voltage drop across each resistor
- show that the voltage drops add up to the battery voltage
I hope this helps! Let me know if you have more questions or would like me to check your results.